2 solutions
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0
#include #include
using namespace std;
string s; int num[256]; //num[i]记录字符i的出现次数 int maxn = 0;
string rev(string s){ //反转s int len = s.length(); for (int i=0;i<len/2;i++) swap(s[i],s[len-i-1]); return s; }
int main(){ getline(cin,s); s = s + ' '; //避免最后一个单词找不到 (没有结尾空格时)
}
- 1
Information
- ID
- 6937
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 70
- Accepted
- 34
- Uploaded By