2 solutions

  • 1
    @ 2024-3-25 11:33:54

    #include #include

    using namespace std;

    string s; int n;

    string calc(string s){ if (s[0]>='a' && s[0]<='z') s[0] = s[0] - 'a' + 'A'; for (int i=1;i<s.length();i++) if (s[i]>='A' && s[i]<='Z') s[i] = s[i] -'A' + 'a'; return s; }

    int main(){ cin >> n; for (int i=1;i<=n;i++){ cin >> s; cout << calc(s) << endl; } }

    • -1
      @ 2024-3-25 11:31:13

      #include #include using namespace std; string s; int n; string calc(string s){ if(s[0]>='a'&&s[0]<='z') s[0]=s[0]-'a'+'A'; for(int i=1;i<s.length();i++) if(s[i]>='A'&&s[i]<='Z') s[i]=s[i]-'A'+'a'; return s; } int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>s; cout<<calc(s)<<endl; } }

      • 1

      Information

      ID
      6932
      Time
      1000ms
      Memory
      128MiB
      Difficulty
      1
      Tags
      # Submissions
      50
      Accepted
      38
      Uploaded By