1 solutions
- 
  0#include #include #include <unordered_map> int main() { int n; std::cin >> n; std::vector<int> samples(n); std::unordered_map<int, int> frequency; for (int i = 0; i < n; ++i) { std::cin >> samples[i]; if (samples[i] <= 100000) { frequency[samples[i]]++; } } for (int i = 0; i <= 100000; ++i) { std::cout << frequency[i] << " \n"; } return 0;} 50分 
- 1
Information
- ID
- 6911
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 9
- Accepted
- 5
- Uploaded By
 
       BC20260080
      
                      LV 9
                    
 @ 2024-4-13 13:03:35
    
          BC20260080
      
                      LV 9
                    
 @ 2024-4-13 13:03:35