2 solutions
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1
#include #include
using namespace std;
string s; int num[256]; //num[i]描述字符i的出现次数 int n;
bool isPrime(int n){ if (n<2) return 0; for (int i=2;i*i<=n;i++) if (n%i==0) return 0; return 1; }
int main(){ cin >> s; for (int i=0;i<=s.length()-1;i++) num[ s[i] ]++;
int maxn = -1e9, minn = 1e9; for (int i='a';i<='z';i++) if (num[i]!=0) { maxn = max(maxn, num[i]); minn = min(minn, num[i]); } if ( isPrime(maxn-minn) ) printf("Lucky Word\n%d\n",maxn-minn); else printf("No Answer\n%d\n",0);
}
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0
#include #include #include using namespace std; int main(){ char a[110]; int ans[26] = {0}; int l,mmax,mmin,delta; scanf("%s",a); l = strlen (a); for(int i =0;i < l;i++) ans[a[i]-'a']++; mmax = 0; mmin =10000; for(int i=0;i <26;i++){ if(ans[i]> mmax) mmax = ans[i]; if(ans[i] != 0 && ans[i] < mmin) mmin =ans[i]; } delta = mmax - mmin; if(delta == 0|| delta == 1){ printf("No Answer\n0\n"); return 0; } for (int h = 2;h*h <= delta;h++) if(delta % h == 0){ printf("No Answer\n0\n"); return 0; } printf("Lucky Word\n%d\n", mmax - mmin); return 0; }
- 1
Information
- ID
- 125
- Time
- 1000ms
- Memory
- 125MiB
- Difficulty
- 2
- Tags
- # Submissions
- 57
- Accepted
- 36
- Uploaded By