1 solutions
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0
#include using namespace std;
int n,m;
int a[105][105]; int b[105][105];
int main(){ cin >> n >> m; for (int i=1;i<=n;i++) for (int j=1;j<=m;j++) cin >> a[i][j];
for (int i=1;i<=n;i++) for (int j=1;j<=m;j++) cin >> b[i][j]; int ans=0; for (int i=1;i<=n;i++) for (int j=1;j<=m;j++) if (a[i][j] == b[i][j]) ans++; printf("%.2lf",ans*100.0/(n*m));
}
- 1
Information
- ID
- 6918
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 63
- Accepted
- 43
- Uploaded By