100 Accepted
ID = 1C4GTiNr4ePnDYqeQsKFRd
| # | Status | Time Cost | Memory Cost |
|---|
| #1 | Accepted | 3ms | 680 KiB |
| #2 | Accepted | 3ms | 684 KiB |
| #3 | Accepted | 3ms | 792 KiB |
| #4 | Accepted | 3ms | 688 KiB |
| #5 | Accepted | 3ms | 688 KiB |
| #6 | Accepted | 3ms | 716 KiB |
| #7 | Accepted | 3ms | 680 KiB |
| #8 | Accepted | 3ms | 680 KiB |
| #9 | Accepted | 3ms | 800 KiB |
| #10 | Accepted | 4ms | 680 KiB |
Information
- Submit By
-
C20250069
LV 10
- Problem
- P1739 表达式括号匹配
- Language
- C++11(O2)
- Submit At
- 2023-10-15 13:28:23
- Judged At
- 2023-10-15 13:28:33
- Score
- 100
- Total Time
- 31ms
- Peak Time
- 4ms
- Peak Memory
- 800 KiB