You are given an integer $k$. Find the largest integer $x$, where $1 \le x < k$, such that $x! + (x - 1)!^\dagger$ is a multiple of $^\ddagger$ $k$, or determine that no such $x$ exists.

$^\dagger$ $y!$ denotes the factorial of $y$, which is defined recursively as $y! = y \cdot (y-1)!$ for $y \geq 1$ with the base case of $0! = 1$. For example, $5! = 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 \cdot 0! = 120$.

$^\ddagger$ If $a$ and $b$ are integers, then $a$ is a multiple of $b$ if there exists an integer $c$ such that $a = b \cdot c$. For example, $10$ is a multiple of $5$ but $9$ is not a multiple of $6$.