#P1196D2. RGB Substring (hard version)
RGB Substring (hard version)
Description
The only difference between easy and hard versions is the size of the input.
You are given a string consisting of characters, each character is 'R', 'G' or 'B'.
You are also given an integer . Your task is to change the minimum number of characters in the initial string so that after the changes there will be a string of length that is a substring of , and is also a substring of the infinite string "RGBRGBRGB ...".
A string is a substring of string if there exists a positive integer such that , , , ..., . For example, strings "GBRG", "B", "BR" are substrings of the infinite string "RGBRGBRGB ..." while "GR", "RGR" and "GGG" are not.
You have to answer independent queries.
The first line of the input contains one integer () — the number of queries. Then queries follow.
The first line of the query contains two integers and () — the length of the string and the length of the substring.
The second line of the query contains a string consisting of characters 'R', 'G' and 'B'.
It is guaranteed that the sum of over all queries does not exceed ().
For each query print one integer — the minimum number of characters you need to change in the initial string so that after changing there will be a substring of length in that is also a substring of the infinite string "RGBRGBRGB ...".
Input
The first line of the input contains one integer () — the number of queries. Then queries follow.
The first line of the query contains two integers and () — the length of the string and the length of the substring.
The second line of the query contains a string consisting of characters 'R', 'G' and 'B'.
It is guaranteed that the sum of over all queries does not exceed ().
Output
For each query print one integer — the minimum number of characters you need to change in the initial string so that after changing there will be a substring of length in that is also a substring of the infinite string "RGBRGBRGB ...".
Note
In the first example, you can change the first character to 'R' and obtain the substring "RG", or change the second character to 'R' and obtain "BR", or change the third, fourth or fifth character to 'B' and obtain "GB".
In the second example, the substring is "BRG".