【深基7.例1】距离函数 - Problem Solution - HFOJ

1
BC20260340 LV 4 @ 2023-12-11 15:43:40
1. #include<bits/stdc++.h>
2. using namespace std;
3. double dis(double a,double b,double c,double d){
4. return sqrt((c-a)\*(c-a)+(d-b)\*(d-b)); } int main(){ double x1,x2,y1,y2,z1,z2;
5. cin>>x1>>x2>>y1>>y2>>z1>>z2;
6. cout<<fixed<<setprecision(2)<<dis(x1,x2,y1,y2)+dis(y1,y2,z1,z2)+dis(z1,z2,x1,x2);
7. return 0; }

ID: 4700
Time: 1000ms
Memory: 125MiB
Difficulty: 1
Tags: (None)
# Submissions: 81
Accepted: 25
Uploaded By: Hydro