1 solutions
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-1
#include #include
using namespace std;
string s; int k;
char calc(string s,int k){ int cnt = 1; for (int i=1;i<=s.length()-1;i++){ if (s[i] == s[i-1]) cnt++; else cnt = 1; if (cnt>=k) return (s[i]); } return '^'; }
int main(){ cin >> k >> s; if (calc(s,k)!='^') cout << calc(s,k); else cout << "No";
}
- 1
Information
- ID
- 6941
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 39
- Accepted
- 32
- Uploaded By